Theorem: Angles opposite to two equal sides of a triangle are equal.
Given: in which AB = AC To Prove: Construction: Draw the bisector AD of which meets BC in D. Proof: In , we have AB = AC [Given] [By construction] AD = AD [Common side] Therefore, by SAS criterion of congruence, we have
[Corresponding parts of congruent triangles are equal] |
Illustration: In and AB = AC. FInd and
Solution: We have, AB = AC [ Angles opp. to equal sides are equal] In we have
Hence, |
is an isosceles triangle with AB = AC. Side BA is produced to D such that AB = AD. Then which of the following is true? | |||
Right Option : C | |||
View Explanation |
In the following figure, AB = AC and DB = DC. Then choose which of the following statement is true?
| |||
Right Option : D | |||
View Explanation |
In the following figure, and are two triangles on the same base BC such that AB = AC and DB = DC. Then which statement is true? | |||
Right Option : B | |||
View Explanation |
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